What is the answer to ln(2.5x^2)=12.83 ?

The answer to ln(2.5x^2)=12.83 is x=sqrt((e^{12.83))/(2.5)},x=-sqrt((e^{12.83))/(2.5)}

Solve for x: ln(2.5x^2)=12.83

The solution is x=sqrt((e^{12.83))/(2.5)},x=-sqrt((e^{12.83))/(2.5)}

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ln (2.5 x^{2}) = 12.83

x = \frac{e ^{12.83}}{2.5}, x = - \frac{e ^{12.83}}{2.5}

Decimal Notation

x = 386.39286 \dots, x = - 386.39286 \dots

Solution steps

ln (2.5 x^{2}) = 12.83

Apply log rules

2.5 x^{2} = e^{12.83}

Solve

2.5 x^{2} = e^{12.83} : x = \frac{e ^{12.83}}{2.5}, x = - \frac{e ^{12.83}}{2.5}

x = \frac{e ^{12.83}}{2.5}, x = - \frac{e ^{12.83}}{2.5}

2.9 = - lo g_{10} (H)

lo g_{3} (x - 11) = 0

lo g_{x} (0.001) = 2

3.81 = - lo g_{10} (ka)

lo g_{10} (x) = 2.644

What is the answer to ln(2.5x^2)=12.83 ?
The answer to ln(2.5x^2)=12.83 is x=sqrt((e^{12.83))/(2.5)},x=-sqrt((e^{12.83))/(2.5)}
Solve for x: ln(2.5x^2)=12.83
The solution is x=sqrt((e^{12.83))/(2.5)},x=-sqrt((e^{12.83))/(2.5)}