What is the answer to log_{3}(x^2-3x-7)=1 ?

The answer to log_{3}(x^2-3x-7)=1 is x=5,x=-2

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log_{3}(x^2-3x-7)=1

lo g_{3} (x^{2} - 3 x - 7) = 1

x = 5, x = - 2

Solution steps

lo g_{3} (x^{2} - 3 x - 7) = 1

Apply log rules

x^{2} - 3 x - 7 = 3

Solve

x^{2} - 3 x - 7 = 3 : x = 5, x = - 2

x = 5, x = - 2

y, x = lo g_{e} (y - 2)

lo g_{4} (x) - lo g_{4} (x - 2) = 2

- ln (1 - p) = 0.002

lo g_{6} (x - 2) = 4 + lo g_{6} (x + 2)

lo g_{4} (x) - lo g_{4} (x + 9) = - 1

What is the answer to log_{3}(x^2-3x-7)=1 ?
The answer to log_{3}(x^2-3x-7)=1 is x=5,x=-2
Solve for x: log_{3}(x^2-3x-7)=1
The solution is x=5,x=-2