What is the answer to solvefor y,x=log_{e}(y-2) ?

The answer to solvefor y,x=log_{e}(y-2) is y=e^x+2

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solvefor y,x=log_{e}(y-2)

solve for

y, x = lo g_{e} (y - 2)

y = e^{x} + 2

Solution steps

x = lo g_{e} (y - 2)

Apply log rules

e^{x} = y - 2

Solve

e^{x} = y - 2 : y = e^{x} + 2

y = e^{x} + 2

lo g_{4} (x) - lo g_{4} (x - 2) = 2

- ln (1 - p) = 0.002

lo g_{6} (x - 2) = 4 + lo g_{6} (x + 2)

lo g_{4} (x) - lo g_{4} (x + 9) = - 1

ln (n^{2} + 12) = ln (- 9 n - 2)

What is the answer to solvefor y,x=log_{e}(y-2) ?
The answer to solvefor y,x=log_{e}(y-2) is y=e^x+2