What is the answer to log_{6}(x-2)=4+log_{6}(x+2) ?

The answer to log_{6}(x-2)=4+log_{6}(x+2) is No Solution for x\in\mathbb{R}

Solve for x: log_{6}(x-2)=4+log_{6}(x+2)

The solution is No Solution for x\in\mathbb{R}

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lo g_{6} (x - 2) = 4 + lo g_{6} (x + 2)

No Solution for x \in R

Solution steps

lo g_{6} (x - 2) = 4 + lo g_{6} (x + 2)

Apply log rules

x - 2 = 1296 (x + 2)

Solve

x - 2 = 1296 (x + 2) : x = - \frac{2594}{1295}

x = - \frac{2594}{1295}

Verify Solutions:

x = - \frac{2594}{1295}

False

The solution is

No Solution for x \in R

lo g_{4} (x) - lo g_{4} (x + 9) = - 1

ln (n^{2} + 12) = ln (- 9 n - 2)

lo g_{2} (x + 1) - 2 lo g_{2} (3) = 3

7.5 = 10.5 + lo g_{10} (x)

lo g_{3} ((r + 10)^{2}) = 4

What is the answer to log_{6}(x-2)=4+log_{6}(x+2) ?
The answer to log_{6}(x-2)=4+log_{6}(x+2) is No Solution for x\in\mathbb{R}
Solve for x: log_{6}(x-2)=4+log_{6}(x+2)
The solution is No Solution for x\in\mathbb{R}