What is the answer to (log_{5}(x))^2=1 ?

The answer to (log_{5}(x))^2=1 is x=5,x= 1/5

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(log_{5}(x))^2=1

(lo g_{5} (x))^{2} = 1

x = 5, x = \frac{1}{5}

Solution steps

(lo g_{5} (x))^{2} = 1

Rewrite the equation with

lo g_{5} (x) = u

(u)^{2} = 1

Solve

u^{2} = 1 : u = 1, u = - 1

u = 1, u = - 1

Substitute back

u = lo g_{5} (x),

solve for

x

Solve

lo g_{5} (x) = 1 : x = 5

Solve

lo g_{5} (x) = - 1 : x = \frac{1}{5}

x = 5, x = \frac{1}{5}

Verify Solutions:

x = 5

True

, x = \frac{1}{5}

True

The solutions are

x = 5, x = \frac{1}{5}

A (x) = ln (x) - 1

2 = lo g_{10} (3 x)

lo g_{4} (lo g_{2} (x + 1)) = 1

x, (f x) = 2 x + ln (x)

3 ln (x - 1) = 0

What is the answer to (log_{5}(x))^2=1 ?
The answer to (log_{5}(x))^2=1 is x=5,x= 1/5
Solve for x: (log_{5}(x))^2=1
The solution is x=5,x= 1/5