What is the answer to log_{4}(log_{2}(x+1))=1 ?

The answer to log_{4}(log_{2}(x+1))=1 is x=15

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log_{4}(log_{2}(x+1))=1

lo g_{4} (lo g_{2} (x + 1)) = 1

x = 15

Solution steps

lo g_{4} (lo g_{2} (x + 1)) = 1

Apply log rules

x + 1 = 16

Solve

x + 1 = 16 : x = 15

x = 15

Verify Solutions:

x = 15

True

The solution is

x = 15

x, (f x) = 2 x + ln (x)

3 ln (x - 1) = 0

lo g_{10} (2 x) + lo g_{10} (5) = 1

8.3 = - lo g_{10} (x)

2 lo g_{5} (x) = 1

What is the answer to log_{4}(log_{2}(x+1))=1 ?
The answer to log_{4}(log_{2}(x+1))=1 is x=15
Solve for x: log_{4}(log_{2}(x+1))=1
The solution is x=15