What is the answer to -9.042=20log_{10}(x) ?

The answer to -9.042=20log_{10}(x) is x= 1/(10^{0.4521)}

Solve for x: -9.042=20log_{10}(x)

The solution is x= 1/(10^{0.4521)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 9.042 = 20 lo g_{10} (x)

x = \frac{1}{1 0 ^{0.4521}}

Decimal Notation

x = 0.35310 \dots

Solution steps

- 9.042 = 20 lo g_{10} (x)

Switch sides

20 lo g_{10} (x) = - 9.042

Divide both sides by

20

lo g_{10} (x) = - 0.4521

Apply log rules

x = \frac{1}{1 0 ^{0.4521}}

Verify Solutions:

x = \frac{1}{1 0 ^{0.4521}}

True

The solution is

x = \frac{1}{1 0 ^{0.4521}}

lo g_{3} (x^{2} + 4 x) = 4

lo g_{3} (81) = 4 lo g_{3} (x + 1)

ln (1.8) - ln (x) = 0.2742

lo g_{10} (x - 1) = 3.4

3 lo g_{5} (25 x) = 12

What is the answer to -9.042=20log_{10}(x) ?
The answer to -9.042=20log_{10}(x) is x= 1/(10^{0.4521)}
Solve for x: -9.042=20log_{10}(x)
The solution is x= 1/(10^{0.4521)}