What is the answer to log_{4}(6x)+log_{4}(x-4)=2 ?

The answer to log_{4}(6x)+log_{4}(x-4)=2 is x=(2(3+sqrt(15)))/3

Solve for x: log_{4}(6x)+log_{4}(x-4)=2

The solution is x=(2(3+sqrt(15)))/3

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lo g_{4} (6 x) + lo g_{4} (x - 4) = 2

x = \frac{2 ( 3 + 15 )}{3}

Decimal Notation

x = 4.58198 \dots

Solution steps

lo g_{4} (6 x) + lo g_{4} (x - 4) = 2

Apply log rules

6 x (x - 4) = 16

Solve

6 x (x - 4) = 16 : x = \frac{2 ( 3 + 15 )}{3}, x = \frac{2 ( 3 - 15 )}{3}

x = \frac{2 ( 3 + 15 )}{3}, x = \frac{2 ( 3 - 15 )}{3}

Verify Solutions:

x = \frac{2 ( 3 + 15 )}{3}

True

, x = \frac{2 ( 3 - 15 )}{3}

False

The solution is

x = \frac{2 ( 3 + 15 )}{3}

ln (x) - x \cdot ln (0.05) = 0

y, ln (y) = ln (5 x) + c

2 ln (5) = ln (- 25 + c)

lo g_{7} (3 x + 1) - (2 x + 8) = 2

lo g_{10} (c + x^{2}) = 2 a

What is the answer to log_{4}(6x)+log_{4}(x-4)=2 ?
The answer to log_{4}(6x)+log_{4}(x-4)=2 is x=(2(3+sqrt(15)))/3
Solve for x: log_{4}(6x)+log_{4}(x-4)=2
The solution is x=(2(3+sqrt(15)))/3