What is the answer to log_{10}(c+x^2)=2a ?

The answer to log_{10}(c+x^2)=2a is x=sqrt(100^a-c),x=-sqrt(100^a-c)

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log_{10}(c+x^2)=2a

lo g_{10} (c + x^{2}) = 2 a

x = 10 0^{a} - c, x = - 10 0^{a} - c

Solution steps

lo g_{10} (c + x^{2}) = 2 a

Apply log rules

c + x^{2} = 10 0^{a}

Solve

c + x^{2} = 10 0^{a} : x = 10 0^{a} - c, x = - 10 0^{a} - c

x = 10 0^{a} - c, x = - 10 0^{a} - c

ln (16 x) - ln (4) = 2

lo g_{10} (y) = 2 t + 4, y

(ln (x))^{2} - ln (x^{3}) - 10 = 0

3 lo g_{3} (x) + lo g_{3} (x^{2}) = 5

x, z = ln (x^{2} y)

What is the answer to log_{10}(c+x^2)=2a ?
The answer to log_{10}(c+x^2)=2a is x=sqrt(100^a-c),x=-sqrt(100^a-c)