What is the answer to log_{7}(3x+1)-(2x+8)=2 ?

The answer to log_{7}(3x+1)-(2x+8)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{7}(3x+1)-(2x+8)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{7} (3 x + 1) - (2 x + 8) = 2

No Solution for x \in R

Solution steps

lo g_{7} (3 x + 1) - (2 x + 8) = 2

Move

(2 x + 8)

to the right side

lo g_{7} (3 x + 1) = 2 x + 10

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

7^{l o g_{7} (3 x + 1)} = 7^{2 x + 10}

Simplify

7^{l o g_{7} (3 x + 1)} : 3 x + 1

3 x + 1 = 7^{2 x + 10}

Solve

3 x + 1 = 7^{2 x + 10} :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (c + x^{2}) = 2 a

ln (16 x) - ln (4) = 2

lo g_{10} (y) = 2 t + 4, y

(ln (x))^{2} - ln (x^{3}) - 10 = 0

3 lo g_{3} (x) + lo g_{3} (x^{2}) = 5

What is the answer to log_{7}(3x+1)-(2x+8)=2 ?
The answer to log_{7}(3x+1)-(2x+8)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{7}(3x+1)-(2x+8)=2
The solution is No Solution for x\in\mathbb{R}