What is the answer to log_{5}(2x)=-1 ?

The answer to log_{5}(2x)=-1 is x= 1/10

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log_{5}(2x)=-1

lo g_{5} (2 x) = - 1

x = \frac{1}{10}

Solution steps

lo g_{5} (2 x) = - 1

Apply log rules

2 x = \frac{1}{5}

Solve

2 x = \frac{1}{5} : x = \frac{1}{10}

x = \frac{1}{10}

lo g_{2} (3 x^{2} - 2 x - 1) = 5

ln (Y) = 3

w, q = a \cdot ln (b w + 1)

ln (Y) = 0

y, - ln (y + 6) = x^{2}