What is the answer to log_{2}(3x^2-2x-1)=5 ?

The answer to log_{2}(3x^2-2x-1)=5 is x= 11/3 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(3x^2-2x-1)=5

lo g_{2} (3 x^{2} - 2 x - 1) = 5

x = \frac{11}{3}, x = - 3

Decimal Notation

x = 3.66666 \dots, x = - 3

Solution steps

lo g_{2} (3 x^{2} - 2 x - 1) = 5

Apply log rules

3 x^{2} - 2 x - 1 = 32

Solve

3 x^{2} - 2 x - 1 = 32 : x = \frac{11}{3}, x = - 3

x = \frac{11}{3}, x = - 3

ln (Y) = 3

w, q = a \cdot ln (b w + 1)

ln (Y) = 0

y, - ln (y + 6) = x^{2}

2 = lo g_{10} (2^{8} \frac{1}{x})

What is the answer to log_{2}(3x^2-2x-1)=5 ?
The answer to log_{2}(3x^2-2x-1)=5 is x= 11/3 ,x=-3
Solve for x: log_{2}(3x^2-2x-1)=5
The solution is x= 11/3 ,x=-3