What is the answer to log_{10}(3x)+log_{10}(x+2)=2 ?

The answer to log_{10}(3x)+log_{10}(x+2)=2 is x=(-3+sqrt(309))/3

Solve for x: log_{10}(3x)+log_{10}(x+2)=2

The solution is x=(-3+sqrt(309))/3

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lo g_{10} (3 x) + lo g_{10} (x + 2) = 2

x = \frac{- 3 + 309}{3}

Solution steps

lo g_{10} (3 x) + lo g_{10} (x + 2) = 2

Apply log rules

3 x (x + 2) = 100

Solve

3 x (x + 2) = 100 : x = \frac{- 3 + 309}{3}, x = - \frac{3 + 309}{3}

x = \frac{- 3 + 309}{3}, x = - \frac{3 + 309}{3}

Verify Solutions:

x = \frac{- 3 + 309}{3}

True

, x = - \frac{3 + 309}{3}

False

The solution is

x = \frac{- 3 + 309}{3}

lo g_{10} (3 x) + lo g_{10} (x + 2) = 7

lo g_{x} (2) + lo g_{2} (x) = 2

lo g_{x} (2) + lo g_{2} (x) = 0

x, ln (3 x - 13) = 3

ln (2 x) - ln (x^{2} - 3) = 0

What is the answer to log_{10}(3x)+log_{10}(x+2)=2 ?
The answer to log_{10}(3x)+log_{10}(x+2)=2 is x=(-3+sqrt(309))/3
Solve for x: log_{10}(3x)+log_{10}(x+2)=2
The solution is x=(-3+sqrt(309))/3