What is the answer to ln(x)+ln(4x)=6 ?

The answer to ln(x)+ln(4x)=6 is x=e^{(6-2ln(2))/2}

Solve for x: ln(x)+ln(4x)=6

The solution is x=e^{(6-2ln(2))/2}

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ln (x) + ln (4 x) = 6

x = e^{\frac{6 - 2 l n ( 2 )}{2}}

Decimal Notation

x = 10.04276 \dots

Solution steps

ln (x) + ln (4 x) = 6

Apply log rules

x = e^{\frac{6 - 2 l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{6 - 2 l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{6 - 2 l n ( 2 )}{2}}

ln (3 x) - 10 = - 8

ln (x) = ln (5) + ln (x - 7)

lo g_{2 x} (2 x^{2} + 6 x - 4) = 2

10 lo g_{10} (x^{2}) = - 20

2 5^{l o g_{5} (3 x^{2})} = 9 x^{2}

What is the answer to ln(x)+ln(4x)=6 ?
The answer to ln(x)+ln(4x)=6 is x=e^{(6-2ln(2))/2}
Solve for x: ln(x)+ln(4x)=6
The solution is x=e^{(6-2ln(2))/2}