What is the answer to log_{3}(4x)=log_{6}(x) ?

The answer to log_{3}(4x)=log_{6}(x) is x= 1/(6^{(2log_{6)(2))/(1-log_{6)(3)}}}

Solve for x: log_{3}(4x)=log_{6}(x)

The solution is x= 1/(6^{(2log_{6)(2))/(1-log_{6)(3)}}}

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lo g_{3} (4 x) = lo g_{6} (x)

x = \frac{1}{6 ^{\frac{2 l o g _{6} ( 2 )}{1 - l o g _{6} ( 3 )}}}

Solution steps

lo g_{3} (4 x) = lo g_{6} (x)

Apply log rules

x = \frac{1}{6 ^{\frac{2 l o g _{6} ( 2 )}{1 - l o g _{6} ( 3 )}}}

Verify Solutions:

x = \frac{1}{6 ^{\frac{2 l o g _{6} ( 2 )}{1 - l o g _{6} ( 3 )}}}

True

The solution is

x = \frac{1}{6 ^{\frac{2 l o g _{6} ( 2 )}{1 - l o g _{6} ( 3 )}}}

lo g_{3} (x + 7) = lo g_{3} (x - 1) + 2

lo g_{3} (x) - lo g_{x} (9) = 0

ln (T) = 1.56 + 0.82 \cdot ln (56)

lo g_{10} (5 k) = 10

- 6 = - ln ((0)^{2} + c_{1})

What is the answer to log_{3}(4x)=log_{6}(x) ?
The answer to log_{3}(4x)=log_{6}(x) is x= 1/(6^{(2log_{6)(2))/(1-log_{6)(3)}}}
Solve for x: log_{3}(4x)=log_{6}(x)
The solution is x= 1/(6^{(2log_{6)(2))/(1-log_{6)(3)}}}