What is the answer to solvefor x,ln(y)=-ln(x)+C ?

The answer to solvefor x,ln(y)=-ln(x)+C is x=(e^C)/y

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solvefor x,ln(y)=-ln(x)+C

solve for

x, ln (y) = - ln (x) + C

x = \frac{e ^{C}}{y}

Solution steps

ln (y) = - ln (x) + C

Move

ln (x)

to the left side

ln (y) + ln (x) = C

Move

ln (y)

to the right side

ln (x) = C - ln (y)

Apply log rules

x = \frac{e ^{C}}{y}

e^{- \frac{2}{3}} + 15 - 10 = ln (c)

5 lo g_{3} (4 x - 3) = 10

lo g_{8} (x - 1) - lo g_{8} (x - 2) = 1

lo g_{2} (x + 7) + lo g_{2} (x - 5) = 6

lo g_{9} (64 - x^{2}) = 1

What is the answer to solvefor x,ln(y)=-ln(x)+C ?
The answer to solvefor x,ln(y)=-ln(x)+C is x=(e^C)/y