What is the answer to log_{4}(2x+6)=log_{4}(4^2) ?

The answer to log_{4}(2x+6)=log_{4}(4^2) is x=5

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log_{4}(2x+6)=log_{4}(4^2)

lo g_{4} (2 x + 6) = lo g_{4} (4^{2})

x = 5

Solution steps

lo g_{4} (2 x + 6) = lo g_{4} (4^{2})

Apply log rules

2 x + 6 = 16

Solve

2 x + 6 = 16 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

ln (x + 4) = 1.997

A, H = k + lo g_{10} (A C)

lo g_{8} (x) + lo g_{8} (x - 2) = 1

ln (1 + x^{2}) = 1

10 = 20 lo g_{10} (\frac{2}{x})

What is the answer to log_{4}(2x+6)=log_{4}(4^2) ?
The answer to log_{4}(2x+6)=log_{4}(4^2) is x=5
Solve for x: log_{4}(2x+6)=log_{4}(4^2)
The solution is x=5