What is the answer to solvefor A,H=k+log_{10}(AC) ?

The answer to solvefor A,H=k+log_{10}(AC) is A=(10^{H-k})/C

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solvefor A,H=k+log_{10}(AC)

solve for

A, H = k + lo g_{10} (A C)

A = \frac{1 0 ^{H - k}}{C}

Solution steps

H = k + lo g_{10} (A C)

Switch sides

k + lo g_{10} (A C) = H

Move

k

to the right side

lo g_{10} (A C) = H - k

Apply log rules

A C = 1 0^{H - k}

Solve

A C = 1 0^{H - k} : A = \frac{1 0 ^{H - k}}{C}

A = \frac{1 0 ^{H - k}}{C}

lo g_{8} (x) + lo g_{8} (x - 2) = 1

ln (1 + x^{2}) = 1

10 = 20 lo g_{10} (\frac{2}{x})

y, ln (y (k (x + 1))) = x

- x - 2 = ln (x - 1)

What is the answer to solvefor A,H=k+log_{10}(AC) ?
The answer to solvefor A,H=k+log_{10}(AC) is A=(10^{H-k})/C