What is the answer to log_{8}(x)+log_{8}(x-2)=1 ?

The answer to log_{8}(x)+log_{8}(x-2)=1 is x=4

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log_{8}(x)+log_{8}(x-2)=1

lo g_{8} (x) + lo g_{8} (x - 2) = 1

x = 4

Solution steps

lo g_{8} (x) + lo g_{8} (x - 2) = 1

Apply log rules

x (x - 2) = 8

Solve

x (x - 2) = 8 : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions:

x = 4

True

, x = - 2

False

The solution is

x = 4

ln (1 + x^{2}) = 1

10 = 20 lo g_{10} (\frac{2}{x})

y, ln (y (k (x + 1))) = x

- x - 2 = ln (x - 1)

x, ln (x - y) = 0.5

What is the answer to log_{8}(x)+log_{8}(x-2)=1 ?
The answer to log_{8}(x)+log_{8}(x-2)=1 is x=4
Solve for x: log_{8}(x)+log_{8}(x-2)=1
The solution is x=4