What is the answer to -x-2=ln(x-1) ?

The answer to -x-2=ln(x-1) is x=\W_{0}(1/(e^3))+1

Solve for x: -x-2=ln(x-1)

The solution is x=\W_{0}(1/(e^3))+1

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- x - 2 = ln (x - 1)

x = W_{0} (\frac{1}{e ^{3}}) + 1

Solution steps

- x - 2 = ln (x - 1)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{- x - 2} = e^{l n (x - 1)}

Simplify

e^{l n (x - 1)} : x - 1

e^{- x - 2} = x - 1

Solve

e^{- x - 2} = x - 1 : x = W_{0} (\frac{1}{e ^{3}}) + 1

x = W_{0} (\frac{1}{e ^{3}}) + 1

Verify Solutions:

x = W_{0} (\frac{1}{e ^{3}}) + 1

True

The solution is

x = W_{0} (\frac{1}{e ^{3}}) + 1

x, ln (x - y) = 0.5

ln (\frac{1.5}{x}) = 27

3 = lo g_{3} (t + 3) + lo g_{3} (t - 3)

lo g_{25} (x + 2) = lo g_{5} (x)

lo g_{5} (t^{2} + 6 t) = lo g_{5} (7)

What is the answer to -x-2=ln(x-1) ?
The answer to -x-2=ln(x-1) is x=\W_{0}(1/(e^3))+1
Solve for x: -x-2=ln(x-1)
The solution is x=\W_{0}(1/(e^3))+1