What is the answer to solvefor y,ln(y(k(x+1)))=x ?

The answer to solvefor y,ln(y(k(x+1)))=x is y=(e^x)/(k(x+1))

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solvefor y,ln(y(k(x+1)))=x

solve for

y, ln (y (k (x + 1))) = x

y = \frac{e ^{x}}{k ( x + 1 )}

Solution steps

ln (y (k (x + 1))) = x

Apply log rules

y k (x + 1) = e^{x}

Solve

y k (x + 1) = e^{x} : y = \frac{e ^{x}}{k ( x + 1 )}

y = \frac{e ^{x}}{k ( x + 1 )}

- x - 2 = ln (x - 1)

x, ln (x - y) = 0.5

ln (\frac{1.5}{x}) = 27

3 = lo g_{3} (t + 3) + lo g_{3} (t - 3)

lo g_{25} (x + 2) = lo g_{5} (x)

What is the answer to solvefor y,ln(y(k(x+1)))=x ?
The answer to solvefor y,ln(y(k(x+1)))=x is y=(e^x)/(k(x+1))