What is the answer to log_{25}(x+2)=log_{5}(x) ?

The answer to log_{25}(x+2)=log_{5}(x) is x=2

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log_{25}(x+2)=log_{5}(x)

lo g_{25} (x + 2) = lo g_{5} (x)

x = 2

Solution steps

lo g_{25} (x + 2) = lo g_{5} (x)

Apply log rules

x + 2 = x^{2}

Solve

x + 2 = x^{2} : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

False

The solution is

x = 2

lo g_{5} (t^{2} + 6 t) = lo g_{5} (7)

ln (4 t) - ln (3 t) = 2

lo g_{10} (m) = - 1 + lo g_{10} (m + 3)

lo g_{2} (4 x + 5) - lo g_{2} (4 - x) = 3

ln (x) = ln^{2} (x)

What is the answer to log_{25}(x+2)=log_{5}(x) ?
The answer to log_{25}(x+2)=log_{5}(x) is x=2
Solve for x: log_{25}(x+2)=log_{5}(x)
The solution is x=2