What is the answer to log_{2}((r+7)^2)=6 ?

The answer to log_{2}((r+7)^2)=6 is r=1,r=-15

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log_{2}((r+7)^2)=6

lo g_{2} ((r + 7)^{2}) = 6

r = 1, r = - 15

Solution steps

lo g_{2} ((r + 7)^{2}) = 6

Apply log rules

(r + 7)^{2} = 64

Solve

(r + 7)^{2} = 64 : r = 1, r = - 15

r = 1, r = - 15

2 ln (3 x) + ln (x - 1) = 0

86 = 20 lo g_{10} (\frac{x}{20})

x, t = 5 ln (x)

ln (3 x^{2} - 2 x) = 0

lo g_{a} (6) = 0.1436

What is the answer to log_{2}((r+7)^2)=6 ?
The answer to log_{2}((r+7)^2)=6 is r=1,r=-15
Solve for r: log_{2}((r+7)^2)=6
The solution is r=1,r=-15