What is the answer to log_{x}(x)-1+log_{x}(x-2)=2 ?

The answer to log_{x}(x)-1+log_{x}(x-2)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{x}(x)-1+log_{x}(x-2)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{x} (x) - 1 + lo g_{x} (x - 2) = 2

No Solution for x \in R

Solution steps

lo g_{x} (x) - 1 + lo g_{x} (x - 2) = 2

Apply log rules

\frac{ln ( x - 2 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( x - 2 )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (x - 2) = 2 ln (x)

Apply log rules

x - 2 = x^{2}

Solve

x - 2 = x^{2} :

No Solution for

x \in R

No Solution for x \in R

lo g_{x} (4) = lo g_{27} (3)

lo g_{10} (3) + lo g_{10} (x) = 23

lo g_{2} (5 x) - 3 lo g_{x} (7) = 0

lo g_{2} (x + 5) - lo g_{2} (x - 1) = 5

6 (ln (4 x - 9)) + 14 = 26

What is the answer to log_{x}(x)-1+log_{x}(x-2)=2 ?
The answer to log_{x}(x)-1+log_{x}(x-2)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{x}(x)-1+log_{x}(x-2)=2
The solution is No Solution for x\in\mathbb{R}