What is the answer to 0=-2log_{9}(3x)+1 ?

The answer to 0=-2log_{9}(3x)+1 is x=1

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0=-2log_{9}(3x)+1

0 = - 2 lo g_{9} (3 x) + 1

x = 1

Solution steps

0 = - 2 lo g_{9} (3 x) + 1

Switch sides

- 2 lo g_{9} (3 x) + 1 = 0

Move

1

to the right side

- 2 lo g_{9} (3 x) = - 1

Divide both sides by

- 2

lo g_{9} (3 x) = \frac{1}{2}

Apply log rules

3 x = 3

Solve

3 x = 3 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{x} (x) - 1 + lo g_{x} (x - 2) = 2

lo g_{x} (4) = lo g_{27} (3)

lo g_{10} (3) + lo g_{10} (x) = 23

lo g_{2} (5 x) - 3 lo g_{x} (7) = 0

lo g_{2} (x + 5) - lo g_{2} (x - 1) = 5

What is the answer to 0=-2log_{9}(3x)+1 ?
The answer to 0=-2log_{9}(3x)+1 is x=1
Solve for x: 0=-2log_{9}(3x)+1
The solution is x=1