What is the answer to log_{x}(4)=log_{27}(3) ?

The answer to log_{x}(4)=log_{27}(3) is x=64

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log_{x}(4)=log_{27}(3)

lo g_{x} (4) = lo g_{27} (3)

x = 64

Solution steps

lo g_{x} (4) = lo g_{27} (3)

Apply log rules

\frac{1}{lo g _{4} ( x )} = \frac{1}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

1 \cdot 3 = lo g_{4} (x) \cdot 1

Simplify

3 = lo g_{4} (x)

Apply log rules

64 = x

Switch sides

x = 64

Verify Solutions:

x = 64

True

The solution is

x = 64

lo g_{10} (3) + lo g_{10} (x) = 23

lo g_{2} (5 x) - 3 lo g_{x} (7) = 0

lo g_{2} (x + 5) - lo g_{2} (x - 1) = 5

6 (ln (4 x - 9)) + 14 = 26

3.1 = - lo g_{10} (x)

What is the answer to log_{x}(4)=log_{27}(3) ?
The answer to log_{x}(4)=log_{27}(3) is x=64
Solve for x: log_{x}(4)=log_{27}(3)
The solution is x=64