What is the answer to log_{4}(6x-7)=1 ?

The answer to log_{4}(6x-7)=1 is x= 11/6

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log_{4}(6x-7)=1

lo g_{4} (6 x - 7) = 1

x = \frac{11}{6}

Solution steps

lo g_{4} (6 x - 7) = 1

Apply log rules

6 x - 7 = 4

Solve

6 x - 7 = 4 : x = \frac{11}{6}

x = \frac{11}{6}

y, ln (9 y) = 2 t + 9

ln (r) + ln (10) = \frac{3}{2}

2 ln (x + 1) + 1 = 0

lo g_{3} (8 x - 15) = 4

x^{2} y - 2 x y^{2} + ln (x) y = x y

What is the answer to log_{4}(6x-7)=1 ?
The answer to log_{4}(6x-7)=1 is x= 11/6
Solve for x: log_{4}(6x-7)=1
The solution is x= 11/6