What is the answer to 2-log_{10}(2+x)=0 ?

The answer to 2-log_{10}(2+x)=0 is x=98

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2-log_{10}(2+x)=0

2 - lo g_{10} (2 + x) = 0

x = 98

Solution steps

2 - lo g_{10} (2 + x) = 0

Move

2

to the right side

- lo g_{10} (2 + x) = - 2

Divide both sides by

- 1

lo g_{10} (2 + x) = 2

Apply log rules

2 + x = 100

Solve

2 + x = 100 : x = 98

x = 98

Verify Solutions:

x = 98

True

The solution is

x = 98

ln (x + 4) - ln (x) = 3

- 1.25 ln (10 - 0.8 x) + 1.4539 = 3

ln (8 w - 6) = ln (6 w)

0 = 20 lo g_{10} (3 x)

b, lo g_{b} (2) = 0.401

What is the answer to 2-log_{10}(2+x)=0 ?
The answer to 2-log_{10}(2+x)=0 is x=98
Solve for x: 2-log_{10}(2+x)=0
The solution is x=98