What is the answer to log_{4}(x^2+2)=3 ?

The answer to log_{4}(x^2+2)=3 is x=sqrt(62),x=-sqrt(62)

Solve for x: log_{4}(x^2+2)=3

The solution is x=sqrt(62),x=-sqrt(62)

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lo g_{4} (x^{2} + 2) = 3

x = 62, x = - 62

Decimal Notation

x = 7.87400 \dots, x = - 7.87400 \dots

Solution steps

lo g_{4} (x^{2} + 2) = 3

Apply log rules

x^{2} + 2 = 64

Solve

x^{2} + 2 = 64 : x = 62, x = - 62

x = 62, x = - 62

32 = 20 lo g_{10} (x)

ln (x) = 3.68193

2 lo g_{3} (7 x - 11) + 6 = 10

lo g_{10} (x^{2} - 3 x + 6) = 1

- 80 = 10 \cdot lo g_{10} (x)

What is the answer to log_{4}(x^2+2)=3 ?
The answer to log_{4}(x^2+2)=3 is x=sqrt(62),x=-sqrt(62)
Solve for x: log_{4}(x^2+2)=3
The solution is x=sqrt(62),x=-sqrt(62)