What is the answer to 2log_{3}(7x-11)+6=10 ?

The answer to 2log_{3}(7x-11)+6=10 is x= 20/7

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2log_{3}(7x-11)+6=10

2 lo g_{3} (7 x - 11) + 6 = 10

x = \frac{20}{7}

Solution steps

2 lo g_{3} (7 x - 11) + 6 = 10

Move

6

to the right side

2 lo g_{3} (7 x - 11) = 4

Divide both sides by

2

lo g_{3} (7 x - 11) = 2

Apply log rules

7 x - 11 = 9

Solve

7 x - 11 = 9 : x = \frac{20}{7}

x = \frac{20}{7}

Verify Solutions:

x = \frac{20}{7}

True

The solution is

x = \frac{20}{7}

lo g_{10} (x^{2} - 3 x + 6) = 1

- 80 = 10 \cdot lo g_{10} (x)

1 + 2 lo g_{1} (x) - lo g_{1} (x + 2) = 0

x, 6.69 = - lo g_{10} (x)

0 = - 2 lo g_{9} (3 x + 1)

What is the answer to 2log_{3}(7x-11)+6=10 ?
The answer to 2log_{3}(7x-11)+6=10 is x= 20/7
Solve for x: 2log_{3}(7x-11)+6=10
The solution is x= 20/7