What is the answer to ln(x)-ln(4x-1)=ln(5) ?

The answer to ln(x)-ln(4x-1)=ln(5) is x= 5/19

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ln(x)-ln(4x-1)=ln(5)

ln (x) - ln (4 x - 1) = ln (5)

x = \frac{5}{19}

Solution steps

ln (x) - ln (4 x - 1) = ln (5)

Add

ln (4 x - 1)

to both sides

ln (x) - ln (4 x - 1) + ln (4 x - 1) = ln (5) + ln (4 x - 1)

Simplify

ln (x) = ln (5) + ln (4 x - 1)

Apply log rules

x = 5 (4 x - 1)

Solve

x = 5 (4 x - 1) : x = \frac{5}{19}

x = \frac{5}{19}

Verify Solutions:

x = \frac{5}{19}

True

The solution is

x = \frac{5}{19}

200 = 12 lo g_{1.5} (t) + 25

lo g_{x} (91) = 2

lo g_{x} (\frac{1}{3}) = - 2

lo g_{2} (2 ω + 5) - lo g_{2} (4 - ω) = 3

- ln (1 - x) = 46152

What is the answer to ln(x)-ln(4x-1)=ln(5) ?
The answer to ln(x)-ln(4x-1)=ln(5) is x= 5/19
Solve for x: ln(x)-ln(4x-1)=ln(5)
The solution is x= 5/19