What is the answer to log_{2}(x)-3log_{10}(x)=2 ?

The answer to log_{2}(x)-3log_{10}(x)=2 is x=10^{(2log_{10}(2))/(1-3log_{10)(2)}}

Solve for x: log_{2}(x)-3log_{10}(x)=2

The solution is x=10^{(2log_{10}(2))/(1-3log_{10)(2)}}

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lo g_{2} (x) - 3 lo g_{10} (x) = 2

x = 1 0^{\frac{2 l o g _{10} ( 2 )}{1 - 3 l o g _{10} ( 2 )}}

Solution steps

lo g_{2} (x) - 3 lo g_{10} (x) = 2

Apply log rules

x = 1 0^{\frac{2 l o g _{10} ( 2 )}{1 - 3 l o g _{10} ( 2 )}}

Verify Solutions:

x = 1 0^{\frac{2 l o g _{10} ( 2 )}{1 - 3 l o g _{10} ( 2 )}}

True

The solution is

x = 1 0^{\frac{2 l o g _{10} ( 2 )}{1 - 3 l o g _{10} ( 2 )}}

x, y = lo g_{a} (7 x - b) + 3

95 = 20 lo g_{10} (\frac{275}{x})

x, ln (y) = lo g_{4} (x)

lo g_{10} (2^{x + 1}) = 3^{x}

1 = \frac{1}{ln ( x )}

What is the answer to log_{2}(x)-3log_{10}(x)=2 ?
The answer to log_{2}(x)-3log_{10}(x)=2 is x=10^{(2log_{10}(2))/(1-3log_{10)(2)}}
Solve for x: log_{2}(x)-3log_{10}(x)=2
The solution is x=10^{(2log_{10}(2))/(1-3log_{10)(2)}}