What is the answer to log_{2}(x)+log_{2}(x-3)=3 ?

The answer to log_{2}(x)+log_{2}(x-3)=3 is x=(3+sqrt(41))/2

Solve for x: log_{2}(x)+log_{2}(x-3)=3

The solution is x=(3+sqrt(41))/2

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lo g_{2} (x) + lo g_{2} (x - 3) = 3

x = \frac{3 + 41}{2}

Decimal Notation

x = 4.70156 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (x - 3) = 3

Apply log rules

x (x - 3) = 8

Solve

x (x - 3) = 8 : x = \frac{3 + 41}{2}, x = \frac{3 - 41}{2}

x = \frac{3 + 41}{2}, x = \frac{3 - 41}{2}

Verify Solutions:

x = \frac{3 + 41}{2}

True

, x = \frac{3 - 41}{2}

False

The solution is

x = \frac{3 + 41}{2}

y x = y ln (cy (x))

lo g_{3} (a - 3) = 1 + lo g_{3} (a - 1)

90 = 10 lo g_{10} (I \cdot 1 0^{12})

- 17.5 = 10 lo g_{10} (\frac{x}{1})

lo g_{5} (x^{2}) = 3.1

What is the answer to log_{2}(x)+log_{2}(x-3)=3 ?
The answer to log_{2}(x)+log_{2}(x-3)=3 is x=(3+sqrt(41))/2
Solve for x: log_{2}(x)+log_{2}(x-3)=3
The solution is x=(3+sqrt(41))/2