What is the answer to log_{2}(x)+log_{2}(x-3)=1 ?

The answer to log_{2}(x)+log_{2}(x-3)=1 is x=(3+sqrt(17))/2

Solve for x: log_{2}(x)+log_{2}(x-3)=1

The solution is x=(3+sqrt(17))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{2} (x) + lo g_{2} (x - 3) = 1

x = \frac{3 + 17}{2}

Decimal Notation

x = 3.56155 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (x - 3) = 1

Apply log rules

x (x - 3) = 2

Solve

x (x - 3) = 2 : x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

Verify Solutions:

x = \frac{3 + 17}{2}

True

, x = \frac{3 - 17}{2}

False

The solution is

x = \frac{3 + 17}{2}

2 ln (x - 5) + ln (x + 8) = 3 ln (x)

lo g_{2} (x) + lo g_{2} (x - 3) = 3

y x = y ln (cy (x))

lo g_{3} (a - 3) = 1 + lo g_{3} (a - 1)

90 = 10 lo g_{10} (I \cdot 1 0^{12})

What is the answer to log_{2}(x)+log_{2}(x-3)=1 ?
The answer to log_{2}(x)+log_{2}(x-3)=1 is x=(3+sqrt(17))/2
Solve for x: log_{2}(x)+log_{2}(x-3)=1
The solution is x=(3+sqrt(17))/2