What is the answer to n=-(log_{10}(p))/(10) ?

The answer to n=-(log_{10}(p))/(10) is p=10^{-10n}

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n=-(log_{10}(p))/(10)

n = - \frac{lo g _{10} ( p )}{10}

p = 1 0^{- 10 n}

Solution steps

n = - \frac{lo g _{10} ( p )}{10}

Switch sides

- \frac{lo g _{10} ( p )}{10} = n

Multiply both sides by

10

- lo g_{10} (p) = 10 n

Divide both sides by

- 1

lo g_{10} (p) = - 10 n

Apply log rules

p = 1 0^{- 10 n}

Verify Solutions:

p = 1 0^{- 10 n}

True

The solution is

p = 1 0^{- 10 n}

\frac{11}{10} = lo g_{2} (x)

x = ln (x + 2)

a, lo g_{b} (2 a) = 4

y, lo g_{10} (x y) = y

x = ln (x + 1)

What is the answer to n=-(log_{10}(p))/(10) ?
The answer to n=-(log_{10}(p))/(10) is p=10^{-10n}