What is the answer to x=ln(x+2) ?

The answer to x=ln(x+2) is x=-\W_{-1}(-1/(e^2))-2,x=-\W_{0}(-1/(e^2))-2

Solve for x: x=ln(x+2)

The solution is x=-\W_{-1}(-1/(e^2))-2,x=-\W_{0}(-1/(e^2))-2

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x = ln (x + 2)

x = - W_{- 1} (- \frac{1}{e ^{2}}) - 2, x = - W_{0} (- \frac{1}{e ^{2}}) - 2

Decimal Notation

x = 1.14619 \dots, x = - 1.84140 \dots

Solution steps

x = ln (x + 2)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{x} = e^{l n (x + 2)}

Simplify

e^{l n (x + 2)} : x + 2

e^{x} = x + 2

Solve

e^{x} = x + 2 : x = - W_{- 1} (- \frac{1}{e ^{2}}) - 2, x = - W_{0} (- \frac{1}{e ^{2}}) - 2

x = - W_{- 1} (- \frac{1}{e ^{2}}) - 2, x = - W_{0} (- \frac{1}{e ^{2}}) - 2

Verify Solutions:

x = - W_{- 1} (- \frac{1}{e ^{2}}) - 2

True

, x = - W_{0} (- \frac{1}{e ^{2}}) - 2

True

The solutions are

x = - W_{- 1} (- \frac{1}{e ^{2}}) - 2, x = - W_{0} (- \frac{1}{e ^{2}}) - 2

a, lo g_{b} (2 a) = 4

y, lo g_{10} (x y) = y

x = ln (x + 1)

\frac{x}{4} = lo g_{2} (x)

x, 0.3 = - lo g_{10} (x)

What is the answer to x=ln(x+2) ?
The answer to x=ln(x+2) is x=-\W_{-1}(-1/(e^2))-2,x=-\W_{0}(-1/(e^2))-2
Solve for x: x=ln(x+2)
The solution is x=-\W_{-1}(-1/(e^2))-2,x=-\W_{0}(-1/(e^2))-2