What is the answer to 2log_{3}(x)=log_{3}(18-x) ?

The answer to 2log_{3}(x)=log_{3}(18-x) is x=(-1+sqrt(73))/2

Solve for x: 2log_{3}(x)=log_{3}(18-x)

The solution is x=(-1+sqrt(73))/2

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2 lo g_{3} (x) = lo g_{3} (18 - x)

x = \frac{- 1 + 73}{2}

Solution steps

2 lo g_{3} (x) = lo g_{3} (18 - x)

Apply log rules

x^{2} = 18 - x

Solve

x^{2} = 18 - x : x = \frac{- 1 + 73}{2}, x = \frac{- 1 - 73}{2}

x = \frac{- 1 + 73}{2}, x = \frac{- 1 - 73}{2}

Verify Solutions:

x = \frac{- 1 + 73}{2}

True

, x = \frac{- 1 - 73}{2}

False

The solution is

x = \frac{- 1 + 73}{2}

ln (1 + 6 y - 2 y^{2}) = 0

ln (11.7 - 2.5 x) = x - 4

lo g_{4} (x + 7) = 3

2 lo g_{2} (4 x + 1) - 1 = 6

lo g_{6} (x + 27) - lo g_{6} (x - 8) = 2

What is the answer to 2log_{3}(x)=log_{3}(18-x) ?
The answer to 2log_{3}(x)=log_{3}(18-x) is x=(-1+sqrt(73))/2
Solve for x: 2log_{3}(x)=log_{3}(18-x)
The solution is x=(-1+sqrt(73))/2