What is the answer to log_{3}(x-2)+1=log_{3}(2x-1) ?

The answer to log_{3}(x-2)+1=log_{3}(2x-1) is x=5

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log_{3}(x-2)+1=log_{3}(2x-1)

lo g_{3} (x - 2) + 1 = lo g_{3} (2 x - 1)

x = 5

Solution steps

lo g_{3} (x - 2) + 1 = lo g_{3} (2 x - 1)

Apply log rules

(x - 2) \cdot 3 = 2 x - 1

Solve

(x - 2) \cdot 3 = 2 x - 1 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{e} (1) = ln (x)

- ln (x) = 2.32

- ln (x) = 2.38

lo g_{2} (x) = 8.16

0 = 0.6552 ln (x) + 948 - 0.1 x + 0.2

What is the answer to log_{3}(x-2)+1=log_{3}(2x-1) ?
The answer to log_{3}(x-2)+1=log_{3}(2x-1) is x=5
Solve for x: log_{3}(x-2)+1=log_{3}(2x-1)
The solution is x=5