What is the answer to solvefor x,ln(y)=5ln(18+x) ?

The answer to solvefor x,ln(y)=5ln(18+x) is x=e^{(ln(y))/5}-18 {y>0}

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solvefor x,ln(y)=5ln(18+x)

solve for

x, ln (y) = 5 ln (18 + x)

x = e^{\frac{l n ( y )}{5}} - 18 {y > 0}

Solution steps

ln (y) = 5 ln (18 + x)

Switch sides

5 ln (18 + x) = ln (y)

Divide both sides by

5

ln (18 + x) = \frac{ln ( y )}{5}

Apply log rules

18 + x = e^{\frac{l n ( y )}{5}}

Solve

18 + x = e^{\frac{l n ( y )}{5}} : x = e^{\frac{l n ( y )}{5}} - 18

x = e^{\frac{l n ( y )}{5}} - 18

Verify Solutions:

x = e^{\frac{l n ( y )}{5}} - 18 {y > 0}

The solution is

x = e^{\frac{l n ( y )}{5}} - 18 {y > 0}

4 lo g_{6} (2) = lo g_{6} (x)

lo g_{2} (x + 1) = 78

lo g_{4} (x^{2}) + 4 lo g_{4} (x) = 4

2 lo g_{10} (n) = lo g_{10} (n^{2})

lo g_{x} (5 \cdot x - 6) = 2

What is the answer to solvefor x,ln(y)=5ln(18+x) ?
The answer to solvefor x,ln(y)=5ln(18+x) is x=e^{(ln(y))/5}-18 {y>0}