What is the answer to log_{4}(x^2)+4log_{4}(x)=4 ?

The answer to log_{4}(x^2)+4log_{4}(x)=4 is x=4^{2/3}

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log_{4}(x^2)+4log_{4}(x)=4

lo g_{4} (x^{2}) + 4 lo g_{4} (x) = 4

x = 4^{\frac{2}{3}}

Decimal Notation

x = 2.51984 \dots

Solution steps

lo g_{4} (x^{2}) + 4 lo g_{4} (x) = 4

Apply log rules

x = 4^{\frac{2}{3}}

Verify Solutions:

x = 4^{\frac{2}{3}}

True

The solution is

x = 4^{\frac{2}{3}}

2 lo g_{10} (n) = lo g_{10} (n^{2})

lo g_{x} (5 \cdot x - 6) = 2

lo g_{3} (2 \cdot x) = 10

(2 x)^{l n (2 x)} = e^{2} (2 x)

lo g_{a} (y) + lo g_{a} (5) = 7

What is the answer to log_{4}(x^2)+4log_{4}(x)=4 ?
The answer to log_{4}(x^2)+4log_{4}(x)=4 is x=4^{2/3}
Solve for x: log_{4}(x^2)+4log_{4}(x)=4
The solution is x=4^{2/3}