What is the answer to 2log_{10}(n)=log_{10}(n^2) ?

The answer to 2log_{10}(n)=log_{10}(n^2) is n>0

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2log_{10}(n)=log_{10}(n^2)

2 lo g_{10} (n) = lo g_{10} (n^{2})

n > 0

Solution steps

2 lo g_{10} (n) = lo g_{10} (n^{2})

Apply log rules

n = n

Both sides are equal

True for all n

Verify Solutions:

n > 0

The solution is

n > 0

lo g_{x} (5 \cdot x - 6) = 2

lo g_{3} (2 \cdot x) = 10

(2 x)^{l n (2 x)} = e^{2} (2 x)

lo g_{a} (y) + lo g_{a} (5) = 7

lo g_{10} (4 x + 8) = 2 + lo g_{10} (3)

What is the answer to 2log_{10}(n)=log_{10}(n^2) ?
The answer to 2log_{10}(n)=log_{10}(n^2) is n>0
Solve for n: 2log_{10}(n)=log_{10}(n^2)
The solution is n>0