What is the answer to log_{x}(1/16)=-8 ?

The answer to log_{x}(1/16)=-8 is x=e^{(ln(2))/2}

Solve for x: log_{x}(1/16)=-8

The solution is x=e^{(ln(2))/2}

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lo g_{x} (\frac{1}{16}) = - 8

x = e^{\frac{l n ( 2 )}{2}}

Decimal Notation

x = 1.41421 \dots

Solution steps

lo g_{x} (\frac{1}{16}) = - 8

Apply log rules

\frac{ln ( \frac{1}{16} )}{ln ( x )} = - 8

Multiply both sides by

ln (x)

\frac{ln ( \frac{1}{16} )}{ln ( x )} ln (x) = - 8 ln (x)

Apply log rules

x = e^{\frac{l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{l n ( 2 )}{2}}

x, ln (y + 3) = 2 ln (x)

3.8 = ln (\frac{2}{x})

lo g_{8} (x) = - \frac{2}{3}

ln (4^{x}) = ln (e^{5 x - 1})

lo g_{2} (3 - x) + lo g_{2} (7 - x) = 5

What is the answer to log_{x}(1/16)=-8 ?
The answer to log_{x}(1/16)=-8 is x=e^{(ln(2))/2}
Solve for x: log_{x}(1/16)=-8
The solution is x=e^{(ln(2))/2}