What is the answer to 3log_{2}(x)-1=log_{2}(27) ?

The answer to 3log_{2}(x)-1=log_{2}(27) is x=2^{(3log_{2}(3)+1)/3}

Solve for x: 3log_{2}(x)-1=log_{2}(27)

The solution is x=2^{(3log_{2}(3)+1)/3}

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3 lo g_{2} (x) - 1 = lo g_{2} (27)

x = 2^{\frac{3 l o g _{2} ( 3 ) + 1}{3}}

Decimal Notation

x = 3.77976 \dots

Solution steps

3 lo g_{2} (x) - 1 = lo g_{2} (27)

Move

1

to the right side

3 lo g_{2} (x) = lo g_{2} (27) + 1

Divide both sides by

3

lo g_{2} (x) = \frac{lo g _{2} ( 27 ) + 1}{3}

Apply log rules

x = 2^{\frac{3 l o g _{2} ( 3 ) + 1}{3}}

Verify Solutions:

x = 2^{\frac{3 l o g _{2} ( 3 ) + 1}{3}}

True

The solution is

x = 2^{\frac{3 l o g _{2} ( 3 ) + 1}{3}}

lo g_{16} (x) = lo g_{4} (x^{2})

ln (x (x - 1)) = ln (x) + ln (x - 1)

lo g_{10} (2 x - 5) = - 1

lo g_{9} (4 x + 4) = 2

lo g_{2} (x) - 1 = 3

What is the answer to 3log_{2}(x)-1=log_{2}(27) ?
The answer to 3log_{2}(x)-1=log_{2}(27) is x=2^{(3log_{2}(3)+1)/3}
Solve for x: 3log_{2}(x)-1=log_{2}(27)
The solution is x=2^{(3log_{2}(3)+1)/3}