What is the answer to log_{8}(8x^2)=1 ?

The answer to log_{8}(8x^2)=1 is x=1,x=-1

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log_{8}(8x^2)=1

lo g_{8} (8 x^{2}) = 1

x = 1, x = - 1

Solution steps

lo g_{8} (8 x^{2}) = 1

Apply log rules

8 x^{2} = 8

Solve

8 x^{2} = 8 : x = 1, x = - 1

x = 1, x = - 1

1 + \frac{1}{x} + ln (x) = 0

y, ln (y - 14) = x + ln (x)

lo g_{5} (x^{2}) + 9 = 2

lo g_{6} (3 x) - lo g_{6} (2 x) + 4 = 0

3 ln (x - 6) = - 3

What is the answer to log_{8}(8x^2)=1 ?
The answer to log_{8}(8x^2)=1 is x=1,x=-1
Solve for x: log_{8}(8x^2)=1
The solution is x=1,x=-1