What is the answer to 6x+12yi=(2x-3)+(2y+3)i ?

The answer to 6x+12yi=(2x-3)+(2y+3)i is x=-3/4 ,y= 3/10

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6x+12yi=(2x-3)+(2y+3)i

6 x + 12 y i = (2 x - 3) + (2 y + 3) i

x = - \frac{3}{4}, y = \frac{3}{10}

Solution steps

6 x + 12 y i = (2 x - 3) + (2 y + 3) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[6 x = 2 x - 3 12 y = 2 y + 3]

[6 x = 2 x - 3 12 y = 2 y + 3] : x = - \frac{3}{4}, y = \frac{3}{10}

x = - \frac{3}{4}, y = \frac{3}{10}

15 + 2 3 x = - 5 x + 2

x^{2} = - 3 i

3 x + 2 x i - 3 y i + 2 y = 0

p = 4 πi r^{2}

z^{2} = - 3 - i

What is the answer to 6x+12yi=(2x-3)+(2y+3)i ?
The answer to 6x+12yi=(2x-3)+(2y+3)i is x=-3/4 ,y= 3/10