What is the answer to 3x+2xi-3yi+2y=0 ?

The answer to 3x+2xi-3yi+2y=0 is x=0,y=0

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3x+2xi-3yi+2y=0

3 x + 2 x i - 3 y i + 2 y = 0

x = 0, y = 0

Solution steps

3 x + 2 x i - 3 y i + 2 y = 0

Rewrite

3 x + 2 x i - 3 y i + 2 y

in standard complex form:

(3 x + 2 y) + (2 x - 3 y) i

(3 x + 2 y) + (2 x - 3 y) i = 0

Rewrite

0

in standard complex form:

0 + 0 i

(3 x + 2 y) + (2 x - 3 y) i = 0 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 x + 2 y = 0 2 x - 3 y = 0]

[3 x + 2 y = 0 2 x - 3 y = 0] : x = 0, y = 0

x = 0, y = 0

p = 4 πi r^{2}

z^{2} = - 3 - i

(x - 1) i + (y + 1) = (1 + i) (4 - 3 i)

3 x - 5 i = 6 - (10 y) i

z^{2} + z + 2 + i = 0

What is the answer to 3x+2xi-3yi+2y=0 ?
The answer to 3x+2xi-3yi+2y=0 is x=0,y=0