What is the answer to 7+i^3-xi=9-i^3-xi ?

The answer to 7+i^3-xi=9-i^3-xi is No Solution

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7+i^3-xi=9-i^3-xi

7 + i^{3} - x i = 9 - i^{3} - x i

No Solution

Solution steps

7 + i^{3} - x i = 9 - i^{3} - x i

Substitute

x = a + bi

7 + i^{3} - (a + bi) i = 9 - i^{3} - (a + bi) i

Expand

(7 + b) + i (- 1 - a) = (9 + b) + i (1 - a)

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[7 + b = 9 + b - 1 - a = 1 - a]

[7 + b = 9 + b - 1 - a = 1 - a] : No Solution

Substitute back

x = a + bi

No Solution

x + 3 y + (3 x - y) i = 6 + 6 i

z^{2} - 2 z i - 2 = 0

(x + i y) - 2 (x - i y) + 7 - 6 i = 0

(2 x - i) + (x - 2 y i) = - 2 i

\frac{( 1 - z )}{( 1 + z )} = 2 i

What is the answer to 7+i^3-xi=9-i^3-xi ?
The answer to 7+i^3-xi=9-i^3-xi is No Solution