What is the answer to 3(5+bi)+2i=2a-7i ?

The answer to 3(5+bi)+2i=2a-7i is a= 15/2 ,b=-3

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3(5+bi)+2i=2a-7i

3 (5 + bi) + 2 i = 2 a - 7 i

a = \frac{15}{2}, b = - 3

Solution steps

3 (5 + bi) + 2 i = 2 a - 7 i

Rewrite

3 (5 + bi) + 2 i

in standard complex form:

15 + (3 b + 2) i

15 + (3 b + 2) i = 2 a - 7 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[15 = 2 a 3 b + 2 = - 7]

[15 = 2 a 3 b + 2 = - 7] : a = \frac{15}{2}, b = - 3

a = \frac{15}{2}, b = - 3

s i P (x) = 2 x - 1, Q (x) = x + 3

2 x - y + (2 x - 3 y - i) i = 0

(a + bi)^{2} + 4 (a + bi) = - 4 - 2 i

z^{2} - (2 + 3 i) z - 5 + i = 0

\frac{( 41 + 3 i )}{65} = \frac{1}{x}

What is the answer to 3(5+bi)+2i=2a-7i ?
The answer to 3(5+bi)+2i=2a-7i is a= 15/2 ,b=-3