What are the solutions to the equation 9=-7x+7x^2 ?

The solutions to the equation 9=-7x+7x^2 are x=(7+sqrt(301))/(14),x=(7-sqrt(301))/(14)

Find the zeros of 9=-7x+7x^2

The zeros of 9=-7x+7x^2 are x=(7+sqrt(301))/(14),x=(7-sqrt(301))/(14)

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9 = - 7 x + 7 x^{2}

x = \frac{7 + 301}{14}, x = \frac{7 - 301}{14}

Decimal Notation

x = 1.73923 \dots, x = - 0.73923 \dots

Solution steps

9 = - 7 x + 7 x^{2}

Switch sides

- 7 x + 7 x^{2} = 9

Move

9

to the left side

- 7 x + 7 x^{2} - 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 7 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 7 ( - 9 )}{2 \cdot 7}

(- 7)^{2} - 4 \cdot 7 (- 9) = 301

x_{1, 2} = \frac{- ( - 7 ) \pm 301}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 301}{2 \cdot 7}, x_{2} = \frac{- ( - 7 ) - 301}{2 \cdot 7}

x = \frac{- ( - 7 ) + 301}{2 \cdot 7} : \frac{7 + 301}{14}

x = \frac{- ( - 7 ) - 301}{2 \cdot 7} : \frac{7 - 301}{14}

The solutions to the quadratic equation are:

x = \frac{7 + 301}{14}, x = \frac{7 - 301}{14}

2 x < 8

7 x^{2} = 3 x^{2} + 25

0 = 2 x^{2} + 3 x

- 4 (3 x + 2) = - 3 (4 x + 5)

What are the solutions to the equation 9=-7x+7x^2 ?
The solutions to the equation 9=-7x+7x^2 are x=(7+sqrt(301))/(14),x=(7-sqrt(301))/(14)
Find the zeros of 9=-7x+7x^2
The zeros of 9=-7x+7x^2 are x=(7+sqrt(301))/(14),x=(7-sqrt(301))/(14)