What is the answer to 0=3y-2xy-3y,0=3x-x^2-6xy ?

The answer to 0=3y-2xy-3y,0=3x-x^2-6xy is y=0,x=0

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0=3y-2xy-3y,0=3x-x^2-6xy

0 = 3 y - 2 x y - 3 y, 0 = 3 x - x^{2} - 6 x y

y = 0, x = 0

Solution steps

0 = 3 y - 2 x y - 3 y

Switch sides

3 y - 2 x y - 3 y = 0

Factor

3 y - 2 x y - 3 y : - 2 y x

- 2 y x = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or x = 0

y = 0

x = 0

The solutions are

y = 0, x = 0

(x + 2) (x - 5) \geq = 0

(x^{2} + 1) (y - y^{2}) = 0

2 x^{7} - 256 x^{4.6} = 0

- 400 (4 x + 1)^{99} = 0

- (1 + x) y = 0

What is the answer to 0=3y-2xy-3y,0=3x-x^2-6xy ?
The answer to 0=3y-2xy-3y,0=3x-x^2-6xy is y=0,x=0